Expectations have changed for my peeps

[ChubRock]

Today I wore shorts to work. I know, let the flogging begin.

I have three kilts and have worn each this week. Though I know that each can be re-worn several times (like a good pair of Jeans before I knew the comfort of kilts) before washing, I chose to be 'regular' today as I await kilt #4.

FIVE people in the first twenty-minutes of my day asked "Where is the kilt?"

I'd say expectations have changed since I began wearing the un-bi-furbicated garments. Tomorrow, I will re-cycle a kilt from earlier in the week. I now have convinced the Mrs. that I need at least five kilts. Sad addiction news for her.

Thought I would share.

[Chas]

Do you think that you might be setting your sights too low when you think weekly? There are after all 20 working days in a month.

Regards

Chas

[KFCarter]

Do you think that you might be setting your sights too low when you think weekly? There are after all 20 working days in a month.

Regards

Chas

Excellent point, Chas, but an incomplete accounting.

20 kilts for the work days in a month
4 that are perfect for Saturday chores
4 more for Saturday evening activities
4 for Sundays... and make that 8 if you attend church, because you'll want to change out of your good church kilt...
12, counting 1 each for various, miscelleaneous "bank" holidays
12 more or less for whichever mid-winter holiday you celebrate
10 at least for each of the significant battle anniversaries, tartan days, etc.

that only accounts for 66... and you're still 32 short of Hamish, so you'd be getting off easy....

[CDNSushi]

Last year, in another thread I devised a mathematical formula for how many kilts a man should own...

Let P = # of pairs of pants owned
Let x = days per week pants are worn
Let t = time of 1 rotation cycle in days (e.g. 365 days)

dp = days spent wearing pants per cycle rotation
dk = days spent wearing kilts per cycle rotation

k = theoretical number of kilts that should be owned for optimal wear

(1a) x/7*t=dp ; (1b) [(7-x)/7]*t=dk

(2) k = dk*(p/dp)

Solve for k.

Theoretical example.

I own 15 pairs of pants that I wear 5 days a week (Mon - Fri) for work. Then I walk around kilted on the weekends. I'm working on a 1 year rotation cycle.

P=15
x=5
t=365

(1a) (5/7)*365=261 dp=261 : (1b) (2/7)*365=104 dk=104

(2) (15/261)*104 = 6

Therfore, I should have 6 kilts in my wardrobe for kicking around on weekends.

[ChubRock]

Last year, in another thread I devised a mathematical formula for how many kilts a man should own...

Let P = # of pairs of pants owned
Let x = days per week pants are worn
Let t = time of 1 rotation cycle in days (e.g. 365 days)

dp = days spent wearing pants per cycle rotation
dk = days spent wearing kilts per cycle rotation

k = theoretical number of kilts that should be owned for optimal wear

(1a) x/7*t=dp ; (1b) [(7-x)/7]*t=dk

(2) k = dk*(p/dp)

Solve for k.

Theoretical example.

I own 15 pairs of pants that I wear 5 days a week (Mon - Fri) for work. Then I walk around kilted on the weekends. I'm working on a 1 year rotation cycle.

P=15
x=5
t=365

(1a) (5/7)*365=261 dp=261 : (1b) (2/7)*365=104 dk=104

(2) (15/261)*104 = 6

Therfore, I should have 6 kilts in my wardrobe for kicking around on weekends.

I will skip the first part of the equation because I have 175 student contact days. That leaves me 190 days a year that I can be kilted. Of course it gets -40f in Minnesota but I don't need pants for those days, right?

Assuming I have twelve pair of pants, I think that means I need 13 kilts.
(12/175)*190=13.02

Correct?

Does the .02 make up for the sporrans?

[JolyStNicholas]

I was called to my tailors last night to view the new red leather he had just received. It was about to rain so I decided to go in shorts, tee shirt and flip flops, and carry the Seton Ancient kilt and fly paid in a tailor bag to keep it dry. When entering his shop that was the first words out of his mouth, "What's with the shorts? Where's the kilt? I think that is the first time he has seen me w/o a kilt on, and he was
right on my case, I explaned to him that at times I do wear other things.

By the way the leather is going to make a GREAT Santa vest!

[Chas]

Last year, in another thread I devised a mathematical formula for how many kilts a man should own...

Let P = # of pairs of pants owned
Let x = days per week pants are worn
Let t = time of 1 rotation cycle in days (e.g. 365 days)

dp = days spent wearing pants per cycle rotation
dk = days spent wearing kilts per cycle rotation

k = theoretical number of kilts that should be owned for optimal wear

(1a) x/7*t=dp ; (1b) [(7-x)/7]*t=dk

(2) k = dk*(p/dp)

Solve for k.

Theoretical example.

I own 15 pairs of pants that I wear 5 days a week (Mon - Fri) for work. Then I walk around kilted on the weekends. I'm working on a 1 year rotation cycle.

P=15
x=5
t=365

(1a) (5/7)*365=261 dp=261 : (1b) (2/7)*365=104 dk=104

(2) (15/261)*104 = 6

Therfore, I should have 6 kilts in my wardrobe for kicking around on weekends.

Now that is my kind of science - I don't understand a word of it, but the answer is the one I want!.

Regards

Chas

[CDNSushi]

Now that is my kind of science - I don't understand a word of it, but the answer is the one I want!.

Regards

Chas

Lol! Glad to do my part... :-)

[dfmacliam]

Do you think that you might be setting your sights too low when you think weekly? There are after all 20 working days in a month.

Regards

Chas

and don't forget the weekend wear, plus a church kilt... 5 will never do.... lol

[Dixiecat]

My equation is a little more simplistic than the one posted above:


X = Y

X being the number of kilts you have.
Y being the number of shoes your wife has.