Expectations have changed for my peeps

[CDNSushi]

Last year, in another thread I devised a mathematical formula for how many kilts a man should own...

Let P = # of pairs of pants owned
Let x = days per week pants are worn
Let t = time of 1 rotation cycle in days (e.g. 365 days)

dp = days spent wearing pants per cycle rotation
dk = days spent wearing kilts per cycle rotation

k = theoretical number of kilts that should be owned for optimal wear

(1a) x/7*t=dp ; (1b) [(7-x)/7]*t=dk

(2) k = dk*(p/dp)

Solve for k.

Theoretical example.

I own 15 pairs of pants that I wear 5 days a week (Mon - Fri) for work. Then I walk around kilted on the weekends. I'm working on a 1 year rotation cycle.

P=15
x=5
t=365

(1a) (5/7)*365=261 dp=261 : (1b) (2/7)*365=104 dk=104

(2) (15/261)*104 = 6

Therfore, I should have 6 kilts in my wardrobe for kicking around on weekends.

[ChubRock]

Last year, in another thread I devised a mathematical formula for how many kilts a man should own...

Let P = # of pairs of pants owned
Let x = days per week pants are worn
Let t = time of 1 rotation cycle in days (e.g. 365 days)

dp = days spent wearing pants per cycle rotation
dk = days spent wearing kilts per cycle rotation

k = theoretical number of kilts that should be owned for optimal wear

(1a) x/7*t=dp ; (1b) [(7-x)/7]*t=dk

(2) k = dk*(p/dp)

Solve for k.

Theoretical example.

I own 15 pairs of pants that I wear 5 days a week (Mon - Fri) for work. Then I walk around kilted on the weekends. I'm working on a 1 year rotation cycle.

P=15
x=5
t=365

(1a) (5/7)*365=261 dp=261 : (1b) (2/7)*365=104 dk=104

(2) (15/261)*104 = 6

Therfore, I should have 6 kilts in my wardrobe for kicking around on weekends.

I will skip the first part of the equation because I have 175 student contact days. That leaves me 190 days a year that I can be kilted. Of course it gets -40f in Minnesota but I don't need pants for those days, right?

Assuming I have twelve pair of pants, I think that means I need 13 kilts.
(12/175)*190=13.02

Correct?

Does the .02 make up for the sporrans?

[JolyStNicholas]

I was called to my tailors last night to view the new red leather he had just received. It was about to rain so I decided to go in shorts, tee shirt and flip flops, and carry the Seton Ancient kilt and fly paid in a tailor bag to keep it dry. When entering his shop that was the first words out of his mouth, "What's with the shorts? Where's the kilt? I think that is the first time he has seen me w/o a kilt on, and he was
right on my case, I explaned to him that at times I do wear other things.

By the way the leather is going to make a GREAT Santa vest!

[Chas]

Last year, in another thread I devised a mathematical formula for how many kilts a man should own...

Let P = # of pairs of pants owned
Let x = days per week pants are worn
Let t = time of 1 rotation cycle in days (e.g. 365 days)

dp = days spent wearing pants per cycle rotation
dk = days spent wearing kilts per cycle rotation

k = theoretical number of kilts that should be owned for optimal wear

(1a) x/7*t=dp ; (1b) [(7-x)/7]*t=dk

(2) k = dk*(p/dp)

Solve for k.

Theoretical example.

I own 15 pairs of pants that I wear 5 days a week (Mon - Fri) for work. Then I walk around kilted on the weekends. I'm working on a 1 year rotation cycle.

P=15
x=5
t=365

(1a) (5/7)*365=261 dp=261 : (1b) (2/7)*365=104 dk=104

(2) (15/261)*104 = 6

Therfore, I should have 6 kilts in my wardrobe for kicking around on weekends.

Now that is my kind of science - I don't understand a word of it, but the answer is the one I want!.

Regards

Chas

[CDNSushi]

Now that is my kind of science - I don't understand a word of it, but the answer is the one I want!.

Regards

Chas

Lol! Glad to do my part... :-)